Top 10 tips for working with gearmotors(1)

gearmotors

1. When specifying, start by determining the required torque at the gearbox output shaft.

A gearmotor‘s purpose is to act as a power transmission component. As such, the two most important factors at the gearbox output shaft are its speed (in rpm) and how much work it can do, as determined by the amount of torque it produces. Typically, gearboxes serve to take motor power, reduce its speed, and magnify its torque. However, when attempting to size a gearmotor for a specific application, focus on the speed and available torque at the gearbox’s output shaft.

This is precisely the point at which many people want to concentrate on the motor input horsepower. However, designers really must start by determining exactly what torque is required at the gearbox output shaft, and then work backwards to determine the motor input horsepower required.

Know the basics: The gearsets (or gear train) inside a gearbox provide a mechanical advantage that multiplies torque from the input side to the gearbox output shaft. This mechanical advantage is called the gearbox ratio, and is the number used to determine the torque multiplication from input to output. For example, a gearbox ratio of 30:1 means that the output side is about 30 times more forceful than the input side. So, if a gearmotor must generate 30 in.-lb full load torque at its output shaft, then input torque must be 1.0 in.-lb. (This simple example does not account for the gear train’s internal losses as measured by its overall efficiency.) Once input torque requirement is known, it’s easy to calculate the required motor input hp needed, based on motor input speed.
Kim Kowalewsky, Leeson Electric

 2. To increase energy efficiency, think carefully about motor type and gearing efficiency.

In some cases, it’s possible to significantly increase gearmotor efficiency by replacing a permanent split capacitor (PSC) ac motor with a permanent magnet dc (PMDC) motor. PSCs may have greater maximum efficiency potential, but their true efficiency can be much lower at the actual application operating load point. Also keep in mind that three-phase driven gearmotors are much more efficient than the single-phase equivalent (for example, 64% vs. 53%) and are more reliable because of their simplified design. However, when three-phase power is unavailable, a variable frequency drive (VFD) is required to convert single-phase input to three-phase output for the gearmotor. Today’s VFDs are economical and easily justified when one considers their built-in features, such as soft starts to reduce mechanical shock and increase equipment life.

To maximize the overall efficiency of a gearmotor system, avoid negating motor efficiency gains with inefficient gearing. While a nice solution for tight spaces, right-angle worm-gear reducers have efficiencies of just 50% or less; in contrast, spur and helical gears used in parallel-shaft reducers are typically about 98% efficient. In really tight spaces, consider an offset parallel-shaft gearmotor solution where higher-efficiency spur and helical gears are stacked in a vertical configuration and the output shaft then forms a space-saving U or S-shaped configuration relative to the driving motor.
Clayton Hinkle, Bison Gear & Engineering Corp.

 3. Beware of under or oversizing the gearmotor.

The most common mistake is improper sizing. Keep in mind that there is more to consider than just the torque and speed requirements of your application. Service factor is critical. The American Gear Manufacturers Association (AGMA) has plenty of useful information to help determine service factor needs for common applications. Disregarding service factor can, and often does, lead to the selection of units that will not last as long as the engineer hopes. Think about this — a gearmotor operating a fan two hours per day sees a lot less stress than a rock crusher operating 24 hours per day. Even if the speed and torque requirements to move the respective loads are the same, the service factors applied to the torque requirement (and thus the resulting gearmotors) are very different.

While undersizing can lead to premature motor failure, oversizing is more of an efficiency issue. The motor half of the gearmotor is typically most efficient at around 80 to 90% of rated full load. Many engineers think that if a 5 hp motor is good, then a 7.5 hp must be better. And a 10? Well, that’s superb! The problem with this logic is that the 10-hp model is basically running unloaded, and its power consumption and efficiency unloaded is much worse than that of the 5 hp properly loaded.
Rich Mintz, SEW Eurodrive

 4. Gearbox efficiency depends on many factors, notably gearbox loading.

Manufacturers often specify motor efficiency. Ditto for gearbox efficiency. However, total system efficiency (motor plus gearbox) is neither clearly understood nor easily calculated. This makes catalog gearbox efficiency specifications unreliable because they typically provide only a single efficiency rating. Efficiency depends on a number of factors, especially gearbox loading, but most manufacturers do not list efficiency tolerances, or the difference in efficiencies between a heavily loaded gearbox and one running under normal loads.

The electrical input power to a gearbox (the product of voltage and current to the motor) multiplied by motor efficiency is the input power to the gearbox. Output power is the gearbox speed and load torque. The ratio of output power to input power equals efficiency.

Power loss in the gearbox is mostly due to friction, which generates heat. In miniature gearboxes, heat is not much of a problem because the power losses (and absolute amounts of power involved) are relatively small. However, large gearboxes use oil coolers and pumps to compensate for gearbox inefficiency. Gearbox friction in turn depends on the quality of the gearing, the number of tooth engagements (how many times one wheel drives another), and the load torque (or how much moment the gearbox must deliver).

A general rule: The lighter the load and the higher the ratio, the less likely it is that a gearbox will actually reach the manufacturer’s specified efficiency. Light loading and high ratios tend to produce poor gearbox efficiencies. Conversely, under heavy loading and with high ratios, a gearbox approaches its theoretical efficiency.
Fritz Faulhaber, MicroMo

 5. Don’t shortcut the math.

When properly selected and then maintained, gearmotors can last indefinitely. Whatever you do, don’t shortcut the math. Selection approaches such as, “Rule of thumb,” “We’ve always done it that way,” and “It broke? Get a bigger one” are not proper ways to select gearmotors. Think about service factor and consider the dynamics. For example, is this a reversing application? If so, what about backlash? Selecting gears and motors is a real science. The best and fastest way is to use software offered by the manufacturer. Many manufacturers have web-based software that lets you select application type and enter parameters such as weight, speed, pulley diameter, and coefficient of friction. The software then runs all of the calculations and selects units for you.
Rich Mintz, SEW Eurodrive

Sourced by : http://www.ekomeri.com/

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